Given f(x) = 3(x2 - 5) + 1 Find f(-3)

f(-3) = -32 for f(x) = 3(2x - 5) + 1

f(-3) = 13 for f(x) = 3(x^2 - 5) + 1

Step-by-step explanation:

f(x) = 3 (2x - 5) + 1

f(-3) = 3 (2(-3) - 5) + 1

f(-3) = 3( -6 - 5 ) + 1

f(-3) = 3( -11 ) + 1

f(-3) = -33 + 1

f(-3) = -32

f(x) = 3(x^2 - 5) + 1

f(-3) = 3((-3)^2 - 5) + 1

f(-3) = 3(9 - 5) + 1

f(-3) = 3(4) + 1

f(-3) = 12 + 1

f(-3) = 13

i am not sure :

step-by-step explanation:

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12