(iv) In A ABC, ZA= 76°, ZB = 48°, ZC =
(A) 66°
(B) 56°
(C) 124°
(D) 28°

So in Triangle ABC angleA = 76, angleB=48 wand we have to find angle C
Here ‘a’ stands for angle
So, aA + aB + aC = 180 (Angle sum property of the triangle)
=> 76+48+C = 180
=> 124+C=180
=> C = 180-124 (as when 124 goes to the right side it signs changes)
C=56
So Answer that we get is C=56 by angle sum property of the triangle.
Hope it helps you!

40 & 50 in the right corner are the complementary angles as when placed in a sum (added together) they make 90°