In the right ∆ABC, BL is an angle bisector. If LB = 1.2 in and LC = 0.6 in. Find: - The distance from L to AB.

- m∠ABC

Distance of L from AB = 0.6 in.

m∠ABC = 60°

Step-by-step explanation:

Given:

LB = 1.2 in

LC = 0.6 in

We have to find the distance of point L to AB or length of LD.

From right triangle ΔBCL,

Sin(∠LBC) =

                 =

                 =

                 =

m∠LBC = 30° [Since ∠LBC is an acute angle]

Since, ∠LBC ≅ ∠LBA

m∠LBA = 30°

Now from right triangle ΔLDC,

sin(∠LBA) =

sin(30)° =

LD = 0.6

Therefore, Distance of point L from AB is 0.6 in.

m∠ABC = m∠ABL + m∠LBC

             = 30° + 30°

             = 60°

i know the answer is 3

step-by-step explanation:

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.