In △ABC, BM is a median, △BMC is equilateral and MC = 3cm. Through M is drawn line l∥AB that intersects CB at point N. Find: - m∠ABC
- The distance from C to AB
- The distance from l to AB

m∠ABC = 60°

The distance from C to AB = 3 cm

The distance from l to AB = 1.5 cm

Step-by-step explanation:

The median of ΔABC = BM

The length of MC = 3 cm

Type of triangle given as ΔBMC  = Equilateral triangle

Line MN is parallel to AB and passes through M intersecting CB at N

Given that BM is a median, we have;

MC = AM = 3 cm

BM  = MC = CB = 3 cm, from ΔBMC  = Equilateral triangle

CN = NB by midpoint theorem

∴ CB = CN + NB = 2·CN = 3 cm

The distance from C to AB = CB = 3 cm

The distance from C to AB = 3 cm

CN = 3/2 = 1.5

CN = NB = 1.5

The distance from l to AB = CN = 1.5 cm

The distance from l to AB = 1.5 cm

m∠ABC = m∠BMC = m∠MBC = 60° Interior angles of an equilateral triangle.

m∠ABC = 60°

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

this excerpt is taken from the book “we shall not be moved : the women’s factory strike of 1909 “ and is written by joan dash. it is the story of the great strike when almost 30thousand women working in factories in america formed a union to fight unsafe working conditions, long working hours and miserable wages.

question: which best states the author’s purpose for including this information in the text?

answer: to challenge the reader’s ideas about a historical event