This exercise uses the radioactive decay model The burial cloth of an Egyptian mummy is estimated to contain 60% of the carbon-14 it contained originally. How long ago was the mummy buried? (The half-life of carbon- 14 is 5730 years. Round your answer to the nearest ten years.)

4257 years

Step-by-step explanation:

Given that:

Half-life of carbon 14 (t1/2) = 5730

Estimated carbon 14 content = 60% of amount of carbon 14 = 0.6

Using the model :

m(t) = mo*e^-rt

Decay rate (r) = In2/t1/2 = 0.00012

mo = initial mass

Hence,

Mass of carbon 14 in mummy m(t) = 0.6mo

0.6mo = mo*e^-(0.00012 * t)

0.6 = e^-(0.00012 * t)

Take the ln of both sides

In(0.6) = - 0.00012t

−0.510825 = - 0.00012t

t = 0.510825 / 0.00012

t = 4256.875

t = 4257 (nearest whole number)

the correct answer is d

hope this

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .