Calista boxes items for a packaging company. She can use only cube-shaped boxes, as shown below. These boxes are available in different sizes.

Calista selects a box with a volume of 8in.3 to package her first order.

• What is the length of each side of the box Calista selected?

•The items for Calista's order do not fit in her box. She needs a box that will hold another
56in.3 of space.
What would the length of each side of this box need to be? Show the work
to explain your answer.

•For her next order, Calista has three cube-shaped objects that need to be packed into the
same box. Two of the objects have a volume of sin. 3 The third object has a volume of
27in.3 What can be the minimum length of each side of the box? Show the work to explain
your answer.

Use words, numbers, and/or pictures to show your work.

0.295in^3

Step-by-step explanation:

I divide the 56 by 8 by 27 and got 295 reaped and i keep the exponent  and the inces

7

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2