Exactly 10 disks are in a bowl. Each is marked with a different counting number selected from 1-10. Gina and Monique each select 5 disks. Two of Gina's disks are 2 and 8. Two of Monique's disks are 7 and 9. What is the largest sum that Gina's disks can have?

31

Step-by-step explanation:

The two disks that we know Gina has are: 2 and 8.

We want to find tha largest sum that Gina's disks can have:

This means that the other 3 disks must be the largest possible ones.

We know that Monique has the disks 7 and 9.

The already taken values are: 2, 7, 8, and 9.

The largest values remaining are:

10, 6 and 5.

Then the largest sum that Gyna's disks can have is given by the scenario where Gina draws these 3 disks, and the sum will be:

2 + 8 + 10 + 6 + 5 = 31

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation:

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.