The length of a rectangle is 2 cm less than 7 times the width. The perimeter is 60 cm. Find the width of the rectangle. HINT: Draw a rectangle and label the longer side l for length and the shorter side w for width. Then write an expression for the length based off of w. Reminder that perimeter is the sum of all of the sides

Step-by-step explanation:

Perimeter of a rectangle = 2L +2W

L is the length

W is the width

If the length of a rectangle is 2 cm less than 7 times the width, then;

L = 7W-2 2

Substitute eqn into the formula for finding the perimeter

P = 2(7W-2)+2W

P = 14W-4+2W

P = 16W-4

If P =60cm

60 = 16W-4

16W = 60+4

16W = 64

W = 64/16

W = 4cm

Hence the width of the rectangle is 4cm

Since l = 7w-

l = 7(4)-2

L = 28-2

L = 26cm

You can proceed and draw a rectangle with the dimension of 4cm by 26cm

i can

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.