Can any kind soul help me please

f(x)= -5

Step-by-step explanation:

Determine the types of roots for quadratic function f(x)= 2x^2 + x - 5 when f(x)= 0. Thus, sketch the graph generally at the x-axis

First, rewrite the equation.

f(x)= 2x^2 + x - 5 Then, subsitute the variables to ZERO (0).

f(0)= 2(0)^2 +  0 - 5

Zero raised to any number is zero.

Remove the zero before -5 because it's unecessary.

f(0)= 2(0) - 5

f(0)= 0 - 5

SIMPLIFY- The final answer is -5

goog may have it for you

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.