Joseph and Dante went trick-or-treating and came back with A LOT of candy. However, when Samantha, Joseph’s little sister, gets back, they find that, not only does she have more candy, but she also has better candy than they do. Samantha agrees to trade some of the candy, but they have to follow her trading rules. 3 Smarties packs = 1 fun-size candy bar

2 Tootsie Pops = 1 Skittles pack

15 candy corn = 1 Smarties pack

5 candy corn = 2 Bit-O-Honeys

3 Tootsie Pops = 1 fun-size candy bar

Based on Samantha’s rules, what item is the most valuable?

Fun size candy bar

Step-by-step explanation:

From the question we see that

3 Smarties packs = 1 fun-size candy bar

also

3 Tootsie Pops = 1 fun-size candy bar

Invariably

3 Smarties packs = 3 Tootsie Pops = 1 fun-size candy bar

Again, we can see that

5 candy corn = 2 Bit-O-Honeys

15 candy corn = 1 Smarties pack,

this means that

3 * 2 Bit-O-Honeys = 1 Smarties pack

6 Bit-O-Honeys = 1 Smarties pack

Again, going back to the first relationship, we agree that

3 * 6 Bit-O-Honeys = 3 Smarties pack

45 candy corn = 18 Bit-O-Honeys = 3 Smarties pack = 3 Tootsie Pops = 1 fun-size candy bar

Now,

2 Tootsie Pops = 1 Skittles pack,

this means that

3 Tootsie Pops = 1½ Skittles pack

45 candy corns = 18 Bit-O-Honeys = 3 Smarties packs = 3 Tootsie Pops = 1½ Skittles pack = 1 fun-size candy bar

From the above relationship, the fun size candy bar is the most valuable

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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