Find the number of five-digit numbers less than 40 000 in which the three-digit numbers formed by a consecutive digits are all divisible by either 17 or 23. Remember, zero cannot be the first digit in a three-digit number. Please show grade 7 math work

Following are the code to this questiuon:

def fiv(y):#defining a method fiv that hold a parameter  

  x = str(y) #defining a variable x that convert the value y in string  

  return three(x[0:3]) and three(x[1:4]) and three(x[2:5])#use return keyword to call the method three  

def three(x): #defining a method three that hold x variable as a parameter

   y = int(x) #use y to convert x in integer

   return y>=100 and (y%17==0 or y%23==0) #use return that gives a value which is divisiable by 17 or 23  

print([y for y in range(10000,40000) if fiv(y)])#use print method to print value

Output:

Please find the attached file.

Step-by-step explanation:

In the above code, two methods "fiv and three" is declared that accepts one variable as a parameter, which can be defined as follows:

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950