Find the number of five-digit numbers less than 40 000 in which the three-digit numbers formed by a consecutive digits are all divisible by either 17 or 23. Remember, zero cannot be the first digit in a three-digit number.

Please show grade 7 math work

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

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answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

where is the graph

step-by-step explanation: