Given \qquad m \angle AOCm∠AOCm, angle, A, O, C is a straight angle. \qquad m \angle AOB = 8x + 51^\circm∠AOB=8x+51 ∘ m, angle, A, O, B, equals, 8, x, plus, 51, degrees \qquad m \angle BOC = 6x - 25^\circm∠BOC=6x−25 ∘ m, angle, B, O, C, equals, 6, x, minus, 25, degrees Find m\angle AOBm∠AOBm, angle, A, O, B:

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to