El tiempo de vida en años de cierta especie es una V. A T con función de densidad: f\left(t\right)=k(1-t)2t2 si t∈(0,1)0 ; o .L Hallar el valor de k Hallar la esperanza de vida. Cuál es la probabilidad de que un ejemplar de esta especie viva menos de 9 meses.

For those of you who don't speak spanish:

The lifetime in years of a certain species is a VA T with a density function: f \ left (t \ right) = k (1-t) 2t2 if t∈ (0,1) 0; o .L Find the value of k Find the life expectancy. What is the probability that a specimen of this species lives less than 9 months.

the solution is 12x-6y

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1