Tony invested his savings in two investment funds. The amount he invested in Fund A was $5000 less than the amount he invested in Fund B. Fund A returned a 5% profit and Fund B returned a 2% profit. How much did he invest in Fund B, if the total profit from the two funds together was $660 ?

The amount that Tony invested in fund B is 13,000.

Step-by-step explanation:

From the information given, you know that the profit from fund A plus the profit from fund B is equal to 660, which can be expressed as:

0.05a+0.02b=660

Also, you know that the amount Tony invested in Fund A was $5000 less than the amount he invested in Fund B, which is:

a=b-5,000

Now, you can replace a=b-5000 in the first equation:

0.05(b-5000)+0.02b=660

0.05b-250+0.02b=660

0.07b=660+250

0.07b=910

b=910/0.07

b=13,000

Finally, you can replace the value of b in a=b-5000 to find the value of a:

a=b-5,000

a=13,000-5,000

a=8,000

According to this, the answer is that the amount that Tony invested in fund B is 13,000.

idk

step-by-step explanation:

use that smart brain

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step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

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factorizing, we get that:

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then, the solutions are: or

nothing extraneous has been found!