Given that SQ¯¯¯¯¯ bisects ∠PSR and ∠SPQ≅∠SRQ, which of the following proves that PS¯¯¯¯¯≅SR¯¯¯¯¯? The figure shows two triangles P Q S and R Q S with a common side S Q.

Answers
A.
1. ∠SPQ≅ ∠SRQ (Given)2. SQ¯¯¯¯¯ bisects ∠PSR. (Given)3. ∠SQP≅∠SQR (Def. of ∠ bisect)4. SQ¯¯¯¯¯≅SQ¯¯¯¯¯ (Reflex. Prop. of ≅)5. △PQS≅△RQS (AAS Steps 1, 3, 4)6. PS¯¯¯¯¯≅SR¯¯¯¯¯ (CPCTC)

B.
1. ∠SPQ≅ ∠SRQ (Given)2. SQ¯¯¯¯¯ bisects ∠PSR. (Given)3. ∠SQP≅∠SQR (Def. of bisect)4. SQ¯¯¯¯¯≅SQ¯¯¯¯¯ (Reflex. Prop. of ≅)5. △PQS≅△RQS (SAS Steps 1, 3, 4)6. PS¯¯¯¯¯≅SR¯¯¯¯¯ (CPCTC)

C.
1. ∠SPQ≅ ∠SRQ (Given)2. SQ¯¯¯¯¯ bisects ∠PSR. (Given)3. SP¯¯¯¯¯≅SR¯¯¯¯¯ (Def. of bisect)4. SQ¯¯¯¯¯≅SQ¯¯¯¯¯ (Sym. Prop. of ≅)5. △PQS≅△RQS (SAS Steps 1, 3, 4)6. PS¯¯¯¯¯≅SR¯¯¯¯¯ (CPCTC)

D.
1. ∠SPQ≅ ∠SRQ (Given)2. SQ¯¯¯¯¯ bisects ∠PSR. (Given)3. ∠PSQ≅∠QSR (Def. of ∠ bisect)4. SQ¯¯¯¯¯≅SQ¯¯¯¯¯ (Reflex. Prop. of ≅)5. △PQS≅△RQS (AAS Steps 1, 3, 4)6. PS¯¯¯¯¯≅SR¯¯¯¯¯ (CPCTC)

Step-by-step explanation:

It is given that ∠SPQ≅∠SRQ

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles S P Q and S R Q are highlighted in red.

It is also given that SQ⎯⎯⎯⎯⎯

bisects ∠PSR

.

By the definition of angle bisector, ∠PSQ≅∠QSR

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are congruent and highlighted in red.

△PQS

and △RQS share a common side SQ⎯⎯⎯⎯⎯, and SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

by the Reflexive Property of Congruence.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Segment S Q is highlighted in red.

Two angles, ∠SPQ

and ∠PSQ, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △PQS are congruent to two angles, ∠SRQ and ∠QSR, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △RQS

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are highlighted in red. Angles S P Q and S R Q are highlighted in red. Side S Q is highlighted in blue.

So, △PQS≅△RQS

by the Angle-Angle-Side (AAS) Congruence Theorem.

PS⎯⎯⎯⎯⎯

and SR⎯⎯⎯⎯⎯ are corresponding sides of congruent triangles, △PQS and △RQS. So, PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

by CPCTC.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Sides S R and S P are congruent and highlighted in red.

Translate these six statements and reasons into a 2

-column proof,

1. ∠SPQ≅∠SRQ

(Given)

2. SQ⎯⎯⎯⎯⎯

bisects ∠PSR

. (Given)

3. ∠PSQ≅∠QSR

(Def. of ∠

bisect)

4. SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

(Reflex. Prop. of ≅

)

5. △PQS≅△RQS

(AAS Steps 1, 3, 4)

6. PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

(CPCTC)

There you go

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

h/o/e/s mad

step-by-step explanation:

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