What is the area of a rectangle with vertices at (−4, 0), (−3, 1) , (0, −2), and (−1, −3)? Enter your answer in the box. Do not round any side lengths.

Given :

Vertices of triangle  (−4, 0), (−3, 1) , (0, −2), and (−1, −3).

To Find :

The area of a rectangle.

Solution :

Breadth of triangle :

Length of triangle :

Now, area is given by :

A = L×B

A = √2×2√5

A = 2√10 units

Therefore, the area is 2√10 units.

Hence, this is the required solution.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2