Suppose 56V% of the population has myopia. If a random sample of size 886886 is selected, what is the probability that the proportion of persons with myopia will be less than 59Y%

0.9608

Step-by-step explanation:

P = 56%

56% = 0.56

1-p

1-0.56

= 0.44

√p(1-p/n

= √0.56(1-0.56)/886

= √0.0002781

= 0.01667

= 0.017

0.59-0.56/0.017

= 1.76

P(z <1.76)

When we check the z table,

Probability is equal to 0.9608

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500