Each of urns I and II has 5 red balls, 3 white balls, and 2 green balls. Urn III has 1 red ball, 1 white ball, and 8 green balls. An urn is selected at random and a ball is drawn. If the ball is green, find the probability that urn III was selected. (Enter your probabilities as fractions.)

The probability of selecting the green ball from urn III is ²/₃

Step-by-step explanation:

Given;

total number of balls in urn I = 10

number of green balls in urn I , = 2

total number of balls in urn II = 10

number of green balls in urn II , = 2

total number of balls in urn III = 10

number of green balls in urn II , = 8

Therefore, the probability of selecting the green ball from urn III is ²/₃

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2