A family of 6 is visiting a mall. The mall has 10 exit doors. Assume random selection. Find the probability that

Complete question is;

A family of 6 is visiting a mall. The mall has 10 exit doors. Assume random selection. Find the probability that

a. No family member chooses the same exit door.

b. Every family member chooses the same exit door.

A) 0.6

B) 0.1

Step-by-step explanation:

A) We are told there are 10 exit doors and the family consists of 6 people.

This implies that for them not to choose the same exit door there will be 6 different doors they will pass.

Thus;

Probability that the no family member chooses the same exit door = 6/10 = 0.6

B) If they all choose the same exit door, it means only 1 out of the 10 exit doors will be used by them.

Thus;

Probability that every family member chooses the same exit door = 1/10 = 0.1

y do u put "subscirbe to ence" on a app for ppl who need with their work?

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )