3. The perimeter of a square is 28 feet. If you increase the length by 2 feet and decrease the width by 1 foot, what is the area of the new figure? A.54 B.40 C.48 D.36

The correct options is;

A. 54

Step-by-step explanation:

The given parameters are;

The perimeter of the square = 28 feet

The increase in the dimension of the length of square = 2 feet

The decrease in the dimension of the width of square = 1 feet

We answer as follows;

Let the length of the side of the square = L

The formula for the perimeter of a square = 4 × L

∴ 4 × L = 28 feet

L =28/4 = 7 feet

L = 7 feet

After applying the given modifications, we have;

The new length, L₁ = L + 2 feet = 7 feet  + 2 feet = 9 feet

The new length, L₁ = 9 feet

The new width, W = L - 1 feet = 7 feet - 1 feet = 6 feet (The width and the length, L of a square are equal)

The new width, W = 6 feet

Therefore;

The area of the new figure = The new length × The new width

Substituting the values gives;

The area of the new figure = 9 feet × 6 feet = 54 feet².

The area of the new figure = 54 feet².

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

step-by-step explanation:

coldest temperature they recorded add me europa2433

europa2433