Enter the equation of the line in slope-intercept form. Slope is 5, and (3, 1) is on the line.

The equation of the line is y

y = 5x-14

Step-by-step explanation:

We should use point-slope form to form our equation:

y-1 = 5(x-3)

y-1 = 5x-15

y = 5x-14

Our equation is now in slope-intercept form.

HTH :)

146%

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)