Is it possible to form a triangle with sides 4in, 3in, 1in?

I’m just doing this for points

Step-by-step explanation:

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2