Which is an equation of the line parallel to 4y-7x=8 and passes through (-4,0)

The correct option is; A.

Step-by-step explanation:

The given equation is 4·y - 7·x = 8

The coordinates of the point the line passes = (-4, 0)

By dividing the given equation by 4, we have;

4·y/4 - 7/4·x = 8/4

Which gives;

y  - 7/4·x = 2

y   = 7/4·x + 2

Which is the equation of a straight line in slope and intercept form, y = m·x + c, with the slope, m = 7/4, and the y-intercept = 2

Given that the required line is parallel to the graph of the equation, 4·y - 7·x = 8, the slopes of both equations are equal we have;

Slope of required line = 7/4, point on the line = (-4, 0), which gives the following point and slope form equation of a straight line;

y - 0 = 7/4 × (x - (-4))

y = 7/4·x + 7/4 × 4 = 7/4·x + 7

The equation of the line is therefore;

y = 7/4·x + 7

the answer would be c:   ax + b = ax + c

step-by-step explanation: