Triangle ABC has vertices A (1,1), B (3,2) and C (0,-2), It is dilated by a scale factor of 1/2 about the origin to create triangle A' B' C'. What is the length in units of side B'C'?

The length is 2.5 units

Step-by-step explanation:

Before we find the value of the length of the side, we need the measure of the coordinates after dilation

B’ = 1/2 B = 1/2(3,2) = (1.5, 1)

C’ = 1/2 C = 1/2( 0,-2) = (0,-1)

The measure of the length is the distance between the two points

Mathematically, that would be;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(0-1.5)^2 + (-1-1)^2

D = √(2.25 + 4)

D = √6.25

D = 2.5 units

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

b.-4 units

all you   do is count how many times you move