Please help! This is immediate! A function is created to model the situation where the day of the month, x, is the independent variable, and the height of low tide, T, is the dependent variable. Plot the two points that we know on a graph. Include a dotted line representing the monthly average low tide height, and appropriately label the axes. Note that x = 1 is July 1. - Would this be a sine or cosine function and why. I can't attach the graph so here is this (please attach a graph along with yours):

The T(x), or the y-axis [Height (feet)] goes:

2, 1.8, 1.6, 1.4, 1.2, 1, 0.8, 0.6, 0.4, 0.2, 0, -0.2 and so on until it ends at -0.6

The x, or x-axis [Dates in July] goes:

-1, 0, 1, 2, 3, through 23.

(Plato Unit Activity: Trigonometric Functions)

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

the first option i believe

step-by-step explanation:

is there more to this question?

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: