estimated that the proportion of students who prefer 2 day a week classes to 1 day a week classes was somewhere in the interval (0.451, 0.872) . If a 95% confidence interval was used, find the point estimate of the proportion and the margin of error

Complete Question

A certain university  estimated that the proportion of students who prefer 2 day a week classes to 1 day a week classes was somewhere in the interval (0.451, 0.872) . If a 95% confidence interval was used, find the point estimate of the proportion and the margin of error

The point estimate is

The margin of error is  

Step-by-step explanation:

 From the question we are that

   The estimate of the proportion of students who prefer 2 day a week classes to 1 day a week classes is (0.451, 0.872)

Generally the point estimate is mathematically represented as

=>  

Generally the margin of error is mathematically represented as

=>  

4 adults and 12 babies

step-by-step explanation:

4 x 7 = 28

12 x 15 = 180

180 + 28 =208

4 x 3 = 12