Heights of young adult women in the United States are approximately Normal with a mean of 64 inches and standard deviation 2.7 inches. What proportion of all young adult women in the United States are taller than 6 feet

The proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is  

Step-by-step explanation:

From the question we are told that

   The mean is  

    The standard deviation is  

Generally  6 feet  is equivalent to 6 * 12 = 72 inches

Generally the proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is mathematically represented as

From the z-table

  The area under the normal  curve to the right corresponding to 2.963  is  

=>  

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz