Suppose that the average number of new clients that a sales representative signs in a month is 22 and that the distribution of this random variable is Poisson. What is the probability that any given sales representative will sign fewer than 15 new clients in a month

0.04769

Step-by-step explanation:

Let the average number of new clients that a sales representative signs in a month be .

Given:

Poisson distribution formula:

The probability that any given sales representative will sign fewer than 15 new clients in a month = P(X<15)

Hence, the probability that any given sales representative will sign fewer than 15 new clients in a month  =0.04769

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: it's a

step-by-step explanation: