Write the equation in slope-intercep tform of the line that passes through(6, −11) and is parallel to the graph of y = −x2/3+ 12.

The equation in slope-intercept form of the line that passes through(6,−11) and is parallel to the graph of y = −x2/3+ 12. is

Step-by-step explanation:

We need to Write the equation in slope-intercept form of the line that passes through(6, −11) and is parallel to the graph of y = −x2/3+ 12.

The general equation of slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

Since both the lines are parallel so, they have same slope. (If 2 lines are parallel they have same slope)

So, slope for our equation will be -2/3 (Taken from the equation of line given y=-2/3x+12 and comparing it with general form y=mx+b the value of m is -2/3 )

Now, we need to find y-intercept using point (6,-11) and slope m= -2/3

We will use equation: y=mx+b

Putting values:

So, value of b is -7

Now, the equation of required line having slope  = -2/3 and b=-7 is:

The equation in slope-intercept form of the line that passes through(6,−11) and is parallel to the graph of y = −x2/3+ 12. is

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: