1) Write an equation of a line in slope intercept form (y = mx + b) with slope -3 going through the point (2,-2). Show your work for full credit.

Step-by-step explanation:

Hey there!

Given; The point is (2,-2) and slope (m) is -3.

Remember to use one point formula while finding the eqaution which has slope and point.

The formula;

(y-y1) = m(x-x1)

Put all values.

(y+2) -3(x-2)

Simplify it and put it on y = mx+b form.

y +2 = -3x + 6

y = -3x +6 - 2

y = -3x + 4

Therefore, the equation is y = -3x +4.

Hope it helps...

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)