The polynomial p(x) = x^2+ax+b has distinct roots 2a and b. Find a + b.

Hello,

As 2a and b are two distinct roots of P(x) we can write the following:

Then, a=1/2 and b=-3/2

a+b=1/2-3/2=-1

thanks

Actually, we cannot simplify by b if b is different from 0 so we should take into account the specific case of b=0 but then we come up with a=-2a so a=0 and then 2a=0 et b=0 and this is not possible because it says that 2a and b are two distinct roots, so the case where b=0 is not possible so we can assume that b is different from 0 and then we can simplify b=2ab by 1=2a, so we are good. the solution is a+b=-1

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

your answer is -9

step-by-step explanation: