Samia normally works 8 hours a day and earns $X per hour. For each hour she works in in excess of 8 hours, she is paid twice her regular rate. If Samia works 12 hours in a
given day, how much will she earn in average per hour along that day?

9514 1404 393

  $(4/3)X

Step-by-step explanation:

Working 12 hours, Samia gets paid for the first 8 hours ...

  8 · ($X) = $8X

For the remaining 4 hours, she is paid ...

  4 · ($2X) = $8X

Then for 12 hours, she is paid a total of ...

  $8X +$8X = $16X

Her average hourly pay is then ...

  total pay / total hours = $16X/12 = $(4/3)X . . . average hourly pay

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )