A 2-kg ball rolls down the hill. by the time it is at the bottom, the balls kinetic energy is 25j what is its velocity at the bottom of the hill

x=half

step-by-step explanation:

ans789

step-by-step explanation:

i would say b) is your answer

sorry if im wrong

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb