A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample of n10 men, the sample mean was found to be 242.6 and the sample standard deviation was 73.33. To find the 95 percent confidence interval estimate for the mean, what is the correct critical value to use?

 Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

, where = sample mean, n= sample size, s= sample standard deviation, = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

Critical t-value :

So, the 95 percent confidence interval estimate for the mean :

The 95 percent confidence interval estimate for the mean:(190.14, 295.06)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation: