Determine the coordinates of Q(6,-4) after a reflection in the line x=2

When a point is reflected, it must be reflected across a line

The coordinate of Q after the reflection is:

So, Q(6,-4) → Q' (2-6, -4)= Q'(-4,-4)

The point is given as:

The line of reflection is given as:

The rule of reflection for is:

For , we have:

So, we have:

Hence, the coordinate of Q after the reflection is:

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Q'(-4,-4)

Step-by-step explanation:

Every line of equation x=a is parallel to y-axis.

Reflection across y axis rule :

(x,y) → (-x, y) i.e. y -coordinate remains same.

Reflection across x=a rule :

(x,y) → (a-x, y)

To determine the coordinates of Q(6,-4) after a reflection in the line x=2.

So,   Q(6,-4) → Q' (2-6, -4)= Q'(-4,-4)

Hence, the required coordinate =Q'(-4,-4)

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