Indira makes a box-and-whisker plot of her data. She finds that the distance from the minimum value to the first quartile is greater than the distance between the third quartile and the maximum value. Which is most likely true?
The mean is greater than the median because the data is skewed to the right.
The mean is greater than the median because the data is skewed to the left. The mean is less than the median because the data is skewed to the right
The mean is less than the median because the data is skewed to the left.

The description of the data distribution in Indira's box-and-whisker plot shows that the data is skewed to the left, therefore, the statement that is most likely true is: D. The mean of the data distribution is less than the median because the data is skewed to the left.

Thus, the description of the data distribution in Indira's box-and-whisker plot shows that the data is skewed to the left, therefore, the statement that is most likely true is: D. The mean of the data distribution is less than the median because the data is skewed to the left.

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the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

hey there : ) your answer would be a.

step-by-step explanation: