The length of a rectangle is 5 more than twice the width. Express the Perimeter and Area of the rectangle as a binomial.

The perimeter is 6w + 10   and the area is 2 + 5w and they are all expressed as a binomial. d

Step-by-step explanation:

The statement says that the length is 5 more than twice the width, and we will represent that by the equation   L = 2w + 5 where L is length and w is the width.

We know that to find the Perimeter of a rectangle we will add twice the length plus twice the width.

The length is 2w +5 and the width is w.

Perimeter=  2l + 2w

Perimeter = 2(2w+5) + 2(w)

Perimeter = 4w + 10 + 2w   This is a trinomial , so convert it into a binomial by combining like terms.

Perimeter =  6w + 10  

The perimeter of the rectangle will be 6w +10 .

Now we know to find the area of a rectangle we will have to multiply the length by the width.

Multiply the length by the width.

Area=(w)(2w+5)

Area = 2w^2 + 5w  

The area will also be  2w^2  +5w.  

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

sorry man i accidentally pressed yes my bad

step-by-step explanation: