Agirl has scores of 79, 70, 78, and 70 on her algebra tests.
a. use an inequality to find the score she must make on the final exam to pass the course with an average of 72 or higher, given that the final exam counts as three tests.

(3x+79+70+78+70)/7 >= 72

(3x +297)/7 >= 72

3x + 297 >= 504

3x >= 207

x >= 69

She must get a 69 or higher to pass with an average of 72 or higher.

Check your work: 69+69+69+79+70+78+70/7 = 72

Final exam = 3 times a regular test = 3x

Average = (3x+79+70+78+70)/7 (7 being the total number of tests)

Has to be greater than or equal to 72

The last one hope it works

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