What are the factors of x2 − 9x − 10?

Using quadratic trinomials usi

Steps in factoring x^2 - bx - c, c is negative

Factor x^2 - 9x - 10

Step 1: Find the two integers whose product is -10 and whose sum is -9

-10 x 1 = -10 -10 + 1 = -9

Step 2: Use -10 and -1 to complete the factors.

x^2 - 9x - 10 = (x + 1)(x - 10)

Step 3: Use foil method to check the factors.

(x + 1)(x - 10) = x^2 - 10x + 1x - 10

= x^2 - 9x - 10

Thus, x^2 - 9x - 10 = (x + 1)(x - 10)

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.

hi

step-by-step explanation: