A photograph 8 cm by 11 cm will be framed. The combined area of the frame and photograph will be 180 cm^2. Algebraically determine the outside dimensions of the frame. **I'm very confused about this question given. It's a quadratic border Area/Perimeter question. I'm not sure I am doing this right so I wanted some assistance.

12 cm x 15 cm

Step-by-step explanation:

if the picture frame thickness is x,

then the frame dimension would be (8+2x) cm by (11+2x) cm

area is (8+2x)(11+2x)=180

solve for x, x= 2, -23/2

x is thickness, so should be >0, so x=2

frame dimension:  12 x 16

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: