A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart and fly directly toward each other. In how many hours will they meet?

Step-by-step explanation:

The combined distance that both planes will cover is 200 miles

Time taken by both planes will be the same (t)

So, the combined distance is

They will meet in .

10/7 hrs

Step-by-step explanation:

Step 1 of 5:Let’s organize the given information. Fill in the Rate column :  

Rate (mph)  Time (h)  Distance (mi)  

1st plane   40

2nd plane   100

Step 2 of 5:Let x hours be the time it will take them to meet. Complete the chart using the formula : Distance= Rate x Time :  

Rate (mph)  Time (h)  Distance (mi)  

1st plane  40                    x

2nd plane  100                   x

Step 3 of 5:We know that the distance between the planes was 200 miles.

Use this to make an equation : 40x+100x=200  

.

Step 4 of 5:Solve the equation :  10/7

Step 5 of 5:Read the problem and answer the question in the problem.

It will take them  

 hours. 10/7 hrs

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!