The y-coordinate of the vertex of the parabolic graph of
f(x) = ax2 + bx + c
is

The vertex of the parabolic graph is,

Given that,

We have to determine,

The y-coordinate of the vertex of the parabolic graph?

According to the equation,

The vertex of a parabola is the point at which the parabola passes through its axis of symmetry.

In case the coefficient of the x² term is positive, and then the vertex will be located at the lowest point on the graph, the point at the base of the “U”-shape.

On the contrary, if the coefficient of the x² term is negative, the vertex will be located at the highest point on the graph, at the top of the “U”-shape.

Therefore,

The vertex of the parabola of the given quadratic equation,

The co-ordinate is founded when x = 0,

Then, The vertex is found at point (0, c) at x = -b\2a,

Hence, The vertex of the parabolic graph is, .

For more details refer to the link given below.

link

hello,

y-coordinate is found by computing f(0)=c

so this is the point (0,c)

the vertex is found for x = -b/(2a)

So this is the point ( -2(2a), -(b^2-4ac)/(4a) )

thanks

none cuz there are no "following statements" regarding the question

step-by-step explanation:

answer: i think one of the answer is $150 and $300?

step-by-step explanation: