How much work is done if a person carries 5n of candy 25m when trick or treating

The amount of work done if a person carries 5n of candy 25m when trick or treating is 125.

In order to determine the amount of  work done we are going to multiply the force by the distance.

Using this formula

Work done = Force  x Distance

Where:

Force = 5n

Distance  = 25m

Let plug in the formula

Work done = 5 x 25

Work done= 125

Inconclusion the amount of work done if a person carries 5n of candy 25m when trick or treating is 125.

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The work done  if a person carries 5n of candy 25m when trick or treating is; 125 J.

We are given;

Force carried; F = 5n

Distance covered; d = 25 m

Now, the formula for work done is given as;

Work done = Force × Distance

Thus;

Work done = 5 × 25

Work done = 125 N.m

In conclusion, the work done  if a person carries 5n of candy 25m when trick or treating is 125 N.m or 125 J.

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step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)