Select the correct answer. What is the equation of the line that has a slope of -4 and goes through (-1.6)?

The Answer is C

Step-by-step explanation:

The typical equation is m= (y-y1)/(x-x1)

You are given the coordinate (-1, 6)

x1= -1

y1= 6

m = -4

The answers show that (y-y1)=m(x-x1)

So, you will just plug in the givens.

yes yes yes yes yes yes yes yes yes

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15