A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+263x+92

8.39 seconds

Step-by-step explanation:

Given the equation which models the height of a rocket:

y=-16x^2+263x+92

Time taken to reach maximum height ; = total total time of flight / 2

Total time of flight is obtained at h = 0

Hence +,

y=-16x^2+263x+92 ; y = 0

-16x^2+263x+92 = 0

Using the Quadratic equation solver :

X = 16.78 or x = -0.3466

Time can't be negative

Hence, total time of flight= 16.78

Therefore, time taken to reach maximum height :

Total time of flight / 2

= 16.78 / 2

= 8.39 seconds

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.