At an opening of a new art gallery, the owner hired a caterer to serve light snacks. The owner created a budget for 150 people to attend the opening, with a per person food cost of $4.25. If the number of guests attending the opening was 56% more than expected, then how much was the final food cost?

$994.5

Step-by-step explanation:

At an opening of a new art gallery, the owner hired a caterer to serve light snacks. The owner created a budget for 150 people to attend the opening, with a per person food cost of $4.25.

Cost for 150 persons =

150 × $4.25 = $637.5

If the number of guests attending the opening was 56% more than expected, then how much was the final food cost?

Percentage increase = Final value - Initial value /Initial value

56% = x - 150/150

Cross Multiply

0.56 × 150 = x - 150

84 = x - 150

x = 150 + 84

x= 234 people

56% increase means 84 extra people came

Total people that came = 234 people

From the question, we know that: per person food cost of $4.25.

Hence

1 person = $4.25

234 persons =

234 × $4.25

= $994.5

Therefore, the final food cost is $994.5

it would take 7/10 of an hour too fill the pool.

step-by-step explanation:

y=sec x is the correct answer

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