The diagram below shows the pathway of an ant A looking for food. Find the total distance covered by the ant.

b. If the ant took 30 minutes to complete its journey, calculate the average speed of the
ant

b. Another ant B also went along the same path but it took 15 minutes more than ant A to
reach the end. What was the average speed of ant B?

270m(total distance)

AntA: 9mpm

AntB: 6mpm

Step-by-step explanation:

By diving the total distance and time it took, you can get the rate; how fast the ants are going per minute

antA: 270/30= 9mpm

Since antB is going 15minutes more than antA just add 15 to the 30 it took antA

antB: 270/45= 6mpm

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42