The resultant of two forces has magnitude 20 N. One of the forces is of magnitude 20√3 N and makes an angleof 30° with the resultant. Then what is the magnitude ofthe other force?

Magnitude of resultant of two forces (R) = 20 N

Magnitude of first force (A) = 20√3

Angle between A & R = 30°

the magnitude of the other force

Let the magnitude of other force be B.

We know that,

R = √(A² + B² + 2ABcos ∅)

According to the question,

→ B = √(A² + R² + 2ARcos 30°)

cos 30° = √3/2

→ B = √(20√3)² + (20)² + 2 * 20√3 * 20 * √3/2

→ B = √(1200 + 400 + 1200)

→ B = √2800

→ B = √7 * √400

→ B = 20√7 N

Therefore, the magnitude of other force will be 20√7 N.

I hope it will help you.

Regards.

→ B = √(A² + R² + 2ARcos 30°)

cos 30° = √3/2

→ B = √(20√3)² + (20)² + 2 * 20√3 * 20 * √3/2

→ B = √(1200 + 400 + 1200)

→ B = √2800

→ B = √7 * √400

→ B = 20√7 N

answer: -1

step-by-step explanation:

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.