The perimeter of a triangle is 74 inches. The length of the first side is twice the length of the second side. The third side is 4 inches more than the first side . Find the length of each side of a triangle

Perimeter of a triangle = 74 inches.

the length of each side of a triangle

Let the length of the first side be x inches.

Hence,

• 2 * Length of the second side = x inches

→ Length of the second side = (x/2) inches

• Length of the third side = (x + 4) inches.

We know that,

Perimeter of a triangle = Sum of its three sides.

Hence,

→ 74 = x + x/2 + x + 4

→ 74 = (2x + x + 2x + 8)/2

→ 74 * 2 = 5x + 8

→ 148 - 8 = 5x

→ 140/5 = x

→ x = 28

Therefore,

Length of first side = x = 28 inches.

Length of second side = x/2 = 28/2 = 14 inches.

Length of third side = x + 4 = 28 + 4 = 32 inches.

Verification:-

Sum of the three sides = 74 inches

→ 28 + 14 + 32 = 74

→ 74 = 74

Hence, verified

I hope it will help you.

Regards.

→ 74 = x + x/2 + x + 4

→ 74 = (2x + x + 2x + 8)/2

→ 74 * 2 = 5x + 8

→ 148 - 8 = 5x

→ 140/5 = x

→ x = 28

Therefore,

Length of first side = x = 28 inches.

Length of second side = x/2 = 28/2 = 14 inches.

Length of third side = x + 4 = 28 + 4 = 32 inches.

yes

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.